the balanced reaction between NaOH and HCl is as follows NaOH + HCl ----> NaCl + H₂O stoichiometry of NaOH to HCl is 1:1 molar mass of NaOH is 40 g/mol number of moles = [tex] \frac{mass present }{molar mass} [/tex] therefore number of NaOH moles - 4.00 g / 40 g/mol = 0.100 mol since molar ratio of HCl to NaOH is 1:1 number of HCl moles required = 0.100 mol Molarity of HCl is 1.0 M this means that a volume of 1 L contains 1.0 mol therefore volume containing 0.100 mol - 0.100 mol / 1.0 mol/L = 0.10 L volume of HCl required = 100 mL
