Let the numbers be x & y
Let x > y
So as the difference of the numbers is 120
We get x - y = 120
Subtracting 120 from both sides and adding y we get
y= x – 120
Now the product of the numbers be P
P= xy
P = x(x-120)
P = x² - 120x
Comparing with[tex] ax^2+bx+c [/tex]
We get
a= 1 & b = -120
The vertex is (h,k)
Where
h = -b/2a = -(-120)/2 = 60
So one part of the number shall be x= 60
Now y = x - 120 = 60 - 120 = -60
The numbers are -60 & 60.
