julibobnar19 julibobnar19

24-04-2018
Mathematics

contestada

write (3i-2/3) - (6i-5) as a complex number in standard form

Respuesta :

CastleRook CastleRook

04-05-2018

The standard form of a complex number is: a+bi
thus evaluating the expression we get:
(3i-2/3)-(6i-5)
opening the parenthesis we get:
3i-2/3-6i+5
=(3i-6i)-2/3+5
=-3i+13/3
thus the standard form will be:
13/3-3i
multiplying through by 3 we get:
13-9i

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CYB3RZACK CYB3RZACK

08-05-2018

The correct answer is B. 13/3 - 3i

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