rousedem6029 rousedem6029
  • 24-03-2018
  • Chemistry
contestada

The reaction of 8.00 g of carbon with excess o2 yields 10.9 g of co2. what is the percent yield of this reaction?

Respuesta :

mkryukova19 mkryukova19
  • 24-03-2018
C+O2----> CO2
8.00g              10.9 g

8.00g C*1 molC/12.0g C= 0.667 mol C
10.2g CO2*1mol/(12.0+2*16.0)=0.232 mol CO2  actual yield
0.667 mol C gives 0.667 mol CO2 theoretical yield
% yield = (actual yield/theoretical yield)*100%=
=(0.232 mol CO2/0.667 mol CO2)*100%= 34.9%
Answer Link

Otras preguntas

what is the ratio of the number of cans to the price 24 packs@ 2 for $9
A polar region tilted away from the sun has six months of winter ___?
How do i write 8.517 in two other forms
Which of the following is pop criticism primarily concerned with? - literary analysis of a product -opinion without evidence for a product -advising the pur
Express the quotient in simplest form.
A method of making large numbers more manageable by turning them into multiples of 10
The area of Arizona is 11400 square mileswhat is the expanded form of this number
Expression 2 5+4x2+6-2x2-1 Insert parentheses in Expression 2 so that it has a value of 19. Then show why your expression has a value of 19.
The tiny magnetic effect of atoms within a domain is due to electrons that are _____.
Valence is the number of electrons an atom must gain or lose in order to _____ its outer energy level or have a stable octet in its outer shell. complete lose g