To solve this problem you must apply the proccedure shown below:
1. You have that the the polynomial being subtracted is 0.6t²+8-18t, therefore, to find the additive inverse of the polynomial, you must multiply it by -1, as following:
(0.6t²+8-18t)
(-1)(0.6t²+8-18t)
2. Therefore, you obtain the following result:
-0.6t²-8+18t
Then, tas you can see, the answer is -0.6t²-8+18t.
