thetrojantv
thetrojantv thetrojantv
  • 24-02-2018
  • Mathematics
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galinasem2 galinasem2
  • 24-02-2018
x=((-3)+-√3²-4×5×(-4))/2×5
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carlosego
carlosego carlosego
  • 24-02-2018
We write the polynomial:
 We have then:
 5x ^ 2 + 3x-4 = 0
 a=5
 b=3
 c=-4
 Applying resolver we have
 x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
 Substituting values:
 x = (- (3) +/- root ((3) ^ 2 - 4 (5) (- 4))) / (2 (5))
 Answer:
 x = (- (3) +/- root ((3) ^ 2 - 4 (5) (- 4))) / (2 (5))
 (option 1)
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