BobBball9599 BobBball9599
  • 25-11-2017
  • Chemistry
contestada

If a buffer solution is 0.190 m in a weak acid (ka = 8.2 × 10-5) and 0.590 m in its conjugate base, what is the ph?\

Respuesta :

W0lf93
W0lf93 W0lf93
  • 07-12-2017
You use the Henderson - Hasselbalch equation pH = pKa + log ([salt]/[acid]) pKa = -log (8.2*10^-5) = 4.081 pH = 4.081 + (0.590/0.190) pH = 4.081 + log 3.105 pH = 4.081 + 0.49206 pH = 4.573
Answer Link

Otras preguntas

which is equivalent to (2-5i)(-2+5i)
What are the steps to solve x+1 over 3 = y-5 over 2, for y
Use scientific notation to perform 0.07x1600/0.0004
A baseball team wants to collect at least 160 cans of food for an upcoming food drive. Team members brought 42 cans of food on Monday and 65 cans of food on Wed
Factor completely 2x^3 + 22x^2 + 36x
What is the successor of the natural number 2012?
frank owns an entire block, which happens to be a perfectly square piece of land. one corner of the block is in the intersection of Slauson ave. and carmelita.
You know the measure of the exterior angle of an isosceles triangle which forms a linear pair with the vertex angle. Describe two ways you can find measures of
What is the successor of the natural number 2012?
What fraction is equivalent to 123.5℅