(a^2^n - a^n - 6) / (a^n + 8) That's a power of 2n the 2n is an exponent

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25-09-2017
Mathematics

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(a^2^n - a^n - 6) / (a^n + 8) That's a power of 2n the 2n is an exponent

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coolstick coolstick · Answer 1 · 2017-09-25T16:50:08+02:00

Using long division, we have

[tex]a^{2}-1 ____________________ a^{n}+8 | a^{2n} -a^{n}-6 -(a^{2n}+8a^{2}) -a^{n}-8a^{2}-6 -(-a^{n}+8) -8a^{2}-14[/tex]

The parenthesis are the result of what we multiply (a^n+8) by (we multiply it by the top expression - we start with a^2 then -1), and what's not is the result of adding the parenthesis to the expression about that.

Our final result is (a^n+8)*(a^2-1)-8a^2-14