Alyssa5101 Alyssa5101

22-09-2017
Mathematics

contestada

the vertex of a parabola is (-2,-20), and it's y intercept is (0,-12). what is the equation of the parabola?

(y=x^2 +x+__)

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Аноним Аноним

23-09-2017

y = a(x + 2)^2 - 20

to find a:-

when x = 0 y = -12 so:-

-12 = a(2)^2 - 20

4a = 20-12 = 8
a = 2

so we have

y = 2(x + 2)^2 - 20

y = 2x^2 + 8x + 8 - 20

y = 2x^2 + 8x - 12 is the answer.

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