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  • 25-03-2024
  • Physics
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A stone weighs 2.5N in air , 1.5N in water and 1.7N in kerosene determine the relative density of kerosene

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MathPhys
MathPhys MathPhys
  • 25-03-2024

Answer:

0.8

Explanation:

Draw a free body diagram of the stone. There are 3 forces:

Weight force mg pulling down,

Buoyancy force ρVg pushing up,

and normal force N pushing up.

Sum of forces:

∑F = ma

N + ρVg − mg = 0

ρVg = mg − N

When the stone is in water:

(1000 kg/m³) V (9.8 m/s²) = 2.5 N − 1.5 N

V = 1.02×10⁻⁴ m³

When the stone is in kerosene:

ρ (1.02×10⁻⁴ m³) (9.8 m/s²) = 2.5 N − 1.7 N

ρ = 800 kg/m³

The density of kerosene relative to water is 800 / 1000 = 0.8.

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