kamvaduduma22 kamvaduduma22
  • 24-08-2017
  • Mathematics
contestada

arrange 31/40, 78%, 0.7 in ascending order

Respuesta :

cookieshyquietw
cookieshyquietw cookieshyquietw
  • 24-08-2017
It would be first 31/40,0.7,78%

It might be wrong

Answer Link
windyyork windyyork
  • 29-08-2019

Answer:  [tex]0.7<\dfrac{31}{40}<78\%[/tex]

Step-by-step explanation:

Since we have given that

[tex]\dfrac{31}{40}[/tex], 78%, 0.7

We need to write in ascending order:

So, firstly, we change it into decimal form:

[tex]\dfrac{31}{40}=0.775[/tex]

and

[tex]78\%=\dfrac{78}{100}=0.78[/tex]

and 0.7

So, now we can compare all the three numbers:

0.70<0.775<0.78

Hence, [tex]0.7<\dfrac{31}{40}<78\%[/tex]

Answer Link

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