katelynn25 katelynn25
  • 24-08-2017
  • Mathematics
contestada

Solve for n. M=n-2/n

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apologiabiology
apologiabiology apologiabiology
  • 24-08-2017
multiply both sides by n
nM=n²-2
minus n both sides
M=n²-n-2
minus M both sides
0=n²-n-2-M
use quadratic formual
for 0=an²+bn+c
[tex]n=\frac{-b+/-\sqrt{b^2-4ac}}{2a}[/tex]

in this case
0=1n²-1n-2-M
a=1
b=-1
c=(-2-M)
so

[tex]n=\frac{-(-1)+/-\sqrt{(-1)^2-4(1)(-2-M)}}{2(1)}[/tex]
[tex]n=\frac{1+/-\sqrt{1+8+4M}}{2}[/tex]
[tex]n=\frac{1+/-\sqrt{9+4M}}{2}[/tex]

so
[tex]n=\frac{1+\sqrt{9+4M}}{2}[/tex] and [tex]n=\frac{1-\sqrt{9+4M}}{2}[/tex]
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