Respuesta :

[tex]\bf \textit{Logarithm of rationals}\\\\ log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y) \\\\\\ \textit{Logarithm Cancellation Rules}\\\\ log_{{ a}}{{ a}}^x\implies x\qquad \qquad {{ a}}^{log_{{ a}}x}=x\\\\ -------------------------------\\\\[/tex]

[tex]\bf log_3(4)-log_3(x)=2\implies log_3\left( \frac{4}{x} \right)=2\impliedby \begin{array}{llll} now\ we\\ exponentialize\\ both\ sides \end{array} \\\\\\ 3^{log_3\left( \frac{4}{x} \right)}=3^2\implies \cfrac{4}{x}=3^2\implies \cfrac{4}{9}=x[/tex]

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