Interpreted as: [tex]y = \frac{14}{x} + 3[/tex]
[tex]y = \frac{14}{x} + 3[/tex]
Step 1) Reflect the original function over the y = x line, as this becomes our inverse (ie swap the values of the x and y-coordinates)
[tex]x = \frac{14}{y} + 3[/tex]
Step 2) Solve for y.
[tex]\frac{14}{y} + 3 = x[/tex]
[tex]\frac{14}{y} = x - 3[/tex]
[tex]y(x - 3) = 14[/tex]
[tex]y = \frac{14}{x - 3}[/tex]
[tex]\therefore y^{-1} = \frac{14}{x - 3}[/tex]
