109 g of water remains unfrozen after transferring 50.2 kj of heat from 260 g of liquid water.
Here given ,
The volume of frozen water is m.
m = LFQ
= 333 kJ/kg x 50.2 kJ
= 0.151 kg
= 151 g.
Consequently, the volume of water that is still liquid is :
260 g − 151 g
= 109 g.
Therefore 109 g of water remains unfrozen.
To learn more about freezing point refer to :
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