The given quadratic equation is expressed as
x^2 - 2x = 1
The first tep is to find the square of half the coefficient of x.
The coefficient of x is - 2
Half of the coefficient of x is 2/2 = - 1
The square of 1 is (- 1)^2
We would add the square of half the coefficient of x to both sides of the equation. It becomes
x^2 - 2x + (-1)^2 = - 1 + (- 1)^2
(x - 1)^2 = - 1 + 1
(x - 1)(x - 1) = 0
x = 1 twice
