Let:
[tex]\begin{gathered} 3x+4y=-2\text{ (1)} \\ 2x-4y=-8\text{ (2)} \end{gathered}[/tex]Using elimination method:
[tex]\begin{gathered} (1)+(2) \\ 3x+2x+4y-4y=-10 \\ 5x=-10 \\ \text{divide both sides by 5:} \\ \frac{5x}{5}=-\frac{10}{5} \\ x=-2 \\ \text{ Replace x into (1)} \\ 3(-2)+4y=-2 \\ 4y=4 \\ \text{divide both sides by 4:} \\ \frac{4y}{4}=\frac{4}{4} \\ y=1 \end{gathered}[/tex]