[tex]\begin{gathered} Enthalpy\text{ }change=sum\text{ }bonds\text{ }broken-sum\text{ }bondsformed \\ \Delta H=2612kJmol^{-1}-3016kJmol^{-1} \\ \Delta H=-404kJmol^{-1} \end{gathered}[/tex]
Reaction is therefore exothermic because the bonds in the products are greater than that of the reactants.
