Given:
The triangle ADC is formed by reflecting the triangle ABC across the line segment AC
So, the triangles ABC and ADC are congruent
The area of the triangle ADC = Area of the triangle ABC
The area of the triangle = 1/2 * base * height
Base = AC = 4 units
Height = BE = 3 units
So, the area will be as follows:
[tex]Area=\frac{1}{2}*AC*BE=\frac{1}{2}*4*3=6[/tex]
So, the answer will be:
Area of the triangle ADC is 6 square units
