The equation for the Volume (V) of the cone given is,
[tex]V=\frac{1}{3}\pi r^2h[/tex]
We are to isolate 'h' in the equation above
SOLUTION
Multiply both sides by 3
[tex]3V=3\times\frac{\pi}{3}r^2h[/tex]
Simplify
[tex]3V=\pi r^2h[/tex]
Divide both sides by πr²
[tex]\frac{3V}{\pi r^2}=\frac{\pi r^2h}{\pi r^2}[/tex]
Simplify
[tex]h=\frac{3V}{\pi r^2}[/tex]
Hence, the answer is
[tex]h=\frac{3V}{\pi r^2}\text{ (OPTION D)}[/tex]
