Solution:
Consider the following inequality:
[tex]-4<\frac{3x-2}{5}\leq6[/tex]
this is equivalent to:
[tex](-4)(5)<3x-2\leq(6)(5)[/tex]
this is equivalent to:
[tex]-20<3x-2\leq30[/tex]
solving for 3x, this is equivalent to:
[tex]-20+2<3x\leq30+2[/tex]
this is equivalent to:
[tex]-18<3x\leq32[/tex]
solving for x, we get:
[tex]-\frac{18}{3}this is equivalent to:
[tex]-6
in interval notation, this is equivalent to:
[tex](-6,\frac{32}{3}\rbrack[/tex]
the solution set on the real line is:
