AhavaK23332
AhavaK23332
25-10-2022
Mathematics
contestada
cos2 0-cos 20 = sin2 0
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JacaiA323362
JacaiA323362
25-10-2022
[tex]\begin{gathered} \cos ^2(x)-\cos (2x)=sen^2(x) \\ \text{ }\cos ^2(x)-sen^2(x)\text{ = }\cos (2x) \\ \end{gathered}[/tex]
According to Double identities
[tex]\cos (2x)=2cos^2(x)-1[/tex][tex]\begin{gathered} \cos ^2(x)-sen^2(x)=2\cos ^2(x)-1 \\ -sen^2(x)=2\cos ^2(x)-\cos ^2(x)-1 \\ -sen^2(x)=\cos ^2(x)-1 \\ 1=\cos ^2(x)+sen^2(x) \end{gathered}[/tex]
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