KeasiaI416112 KeasiaI416112
  • 25-10-2022
  • Mathematics
contestada

Log^5(1/25)=-2 in exponential form

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KayseB414181 KayseB414181
  • 25-10-2022

We'll use the follwowing property, which comes from the definition of a logarithm:

[tex]\log _ab=c\Leftrightarrow a^c=b[/tex]

i.e, The logarithm with base a of b is c if, and only if a to the c power equals b.

Using this to translate

[tex]\log _5(\frac{1}{25})=-2[/tex]

Into exponential form, will yield:

[tex]5^{-2}[/tex]

Because:

[tex]5^{-2}=\frac{1}{25}[/tex]

ANSWER:

[tex]5^{-2}[/tex]

Answer Link

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