The electric field is found as 5.76 * 10^-17 Volts.
What is the magnitude of the electric field?
Now we know that the electric field is the region in space where the influence of the charge is felt. We are told that the magnitude of the charge is about 40 e.
Reacll that;
E = Kq/r^2
K = electric constant
q = magnitude of charge
r = distance
Thus;
E = 9 * 10^9 * 40 * 1.6 * 10^-19/1^2
E = 5.76 * 10^-17 Volts
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