Answer: Option (1)
Step-by-step explanation:
[tex]3x^3 - 6x^2 + 30x-20=-20\\\\3x^3 - 6x^2 + 30x=0\\\\3x(x^2 - 2x+10)=0\\\\[/tex]
So, either [tex]x=0[/tex] or [tex]x^2 -2x +10=0[/tex]
For the second case, we know x=0.
For the second case, we can use the quadratic formula.
[tex]x=\frac{2 \pm \sqrt{(-2)^2 - 4(1)(10)}}{2}\\\\x=1 \pm 3i[/tex]
