Answer:
1 mole of Al2O3 = 102 grams
1 mole of Al2 = 54 grams
102 grams of Al2O3 contains = 54 gram of Al2
10kg of Al2O3 contains = (54/102)*10000g Al2
= 5294.11 g Al2 or 5.29411 kg
Answer:
108
Explanation:
Molar mass of Al2O3 = (27 × 2) + (16 × 3)
= 54 + 48 = 102 g/mol
Moles in 204 g of Al2O3 = 204 g/(102 g/mol)
2 mol
Mass of aluminum in 1 mol of Al2O3 = 27 g × 2
= 54 g
Mass of aluminum in 2 mol of Al2O3 = 54 g × 2
= 108 g
