Answer:
[tex]\Longrightarrow: \boxed{\sf{25x^2-30x+9}}[/tex]
Step-by-step explanation:
Isolate the term of x from one side of the equation.
Use the perfect square formula.
[tex]\underline{\text{PERFECT SQUARE FORMULA:}}[/tex]
[tex]\Longrightarrow: \sf{(A-B)^2=A^2-2AB+B^2}[/tex]
(5x-3)²
(5x-3)²= (5x)²-2*5x*3+3²
Solve.
[tex]\sf{(5x)^2-2*5x*3+3^2=\boxed{\sf{25x^2-30x+9}}}[/tex]
Answer:
Step-by-step explanation:
The identity
In this case, a = 5x and b = 3, so substituting the values :