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A heavy liquid with a density 13 g/cm3
is
poured into a U-tube as shown in the lefthand figure below. The left-hand arm of the
tube has a cross-sectional area of 9.55 cm2
,
and the right-hand arm has a cross-sectional
area of 6.08 cm2
. A quantity of 90.8 g of a
light liquid with a density 0.86 g/cm3
is then
poured into the right-hand arm as shown in
the right-hand figure below.
h1
h2
9.55 cm2
6.08 cm2
heavy liquid
13 g/cm3
L
9.55 cm2
6.08 cm2
light liquid
0.86 g/cm3
Determine the height L of the light liquid
in the column in the right arm of the U-tube,
as shown in the second figure above.
Answer in units of cm.

Part 2
Find the pressure on the window.
Answer in units of N/m

Respuesta :

mickymike92

Based on the data provided;

  • the height of the liquid, L is 17.2 cm
  • the pressure on the window is 1449.616 N/m

What is the formula for density?

The formula for calculating density is given as:

  • Density = mass/volume

From the formula above;

mass = density × volume

also, volume = area × height

Therefore,

mass = density × area × height

  • height = mass / (density × area)

Calculating for the height of the liquid:

Height, L = 90.8 / (0.86 × 6.08)

L = 17.2 cm

What is pressure due to a liquid?

The pressure due to a liquid is calculated using the formula below:

  • Pressure = hpg

where;

h is height = 17.2 cm = 0.172 m

P is density = 0.86 g/cm^3 = 860 kg/m^3

g is acceleration due to gravity = 9.8 m/s^2

Pressure = 860 kg/m^3 × 0.172 m × 9.8 m/s^2

Pressure = 1449.616 N/m

Learn more about density and pressure at: https://brainly.com/question/16396974

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