ecassat
ecassat ecassat
  • 22-02-2022
  • Mathematics
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what is the radius of the circle whose equation is x2+y2=18​

Respuesta :

semsee45
semsee45 semsee45
  • 22-02-2022

Answer:

r = [tex]3\sqrt{2}[/tex]

Step-by-step explanation:

equation of a circle:  [tex](x-a)^2+(y-b)^2=r^2[/tex]

where (a, b) is the center and r is the radius

Therefore, for the equation [tex]x^2+y^2=18[/tex]

  • a = 0
  • b = 0
  • r² = 18

⇒ r = [tex]\sqrt{18}[/tex] = [tex]3\sqrt{2}[/tex]

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