thec0mmunity71
thec0mmunity71 thec0mmunity71
  • 23-11-2021
  • Mathematics
contestada

Find an equation for the perpendicular bisector of the line segment whose endpoints
are (6,8) and (-2, -8).

Respuesta :

xenia168
xenia168 xenia168
  • 23-11-2021

Answer:

y = [tex]-\frac{1}{2}[/tex] x + 1

Step-by-step explanation:

( - 2 , - 8 )

( 6 , 8 )

Midpoint of the line segment is ( [tex]\frac{-2+6}{2}[/tex] , [tex]\frac{-8+8}{2}[/tex] ) = ( 2 , 0 )

Slope of segment m = [tex]\frac{-8-8}{-2-6}[/tex] = 2

Slope of perpendicular line to the segment is [tex]-\frac{1}{2}[/tex]

An equation for the perpendicular bisector of the line segment is

y - 0 = [tex]-\frac{1}{2}[/tex] ( x - 2 )

y = [tex]-\frac{1}{2}[/tex] x + 1

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