knhaynes6810 knhaynes6810
  • 21-10-2021
  • Mathematics
contestada

Find an equation of the circle whose diameter has endpoints (-4,-6) and (-6, 4). ​

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evgeniylevi
evgeniylevi evgeniylevi
  • 21-10-2021

Answer:

[tex](x+5)^2+(y+1)^2=104.[/tex]

Step-by-step explanation:

1) the equation of the circle is: (x-x₀)²+(y-y₀)²=r², where point(x₀;y₀) - centre of the circle, r - radius of the circle.

2) the coordinates of the centre are:

[tex]x_0=\frac{-4-6}{2} =-5;[/tex]

[tex]y_0=\frac{4-6}{2}=-1;[/tex]

3) the radius is the distance between (-5;-1) and (-4;-6):

[tex]r^2=\sqrt{(-4+6)^2+(-6-4)^2}=\sqrt{104};[/tex]

4) finally, the required equation is:

(x+5)²+(y+1)²=(√104)².

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