pdt1301281 pdt1301281
  • 21-09-2021
  • Mathematics
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x^{2} =(2x-1)^{2} please hep me

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discipulus
discipulus discipulus
  • 21-09-2021

Answer:

[tex] {x}^{2} = {(2x - 1)}^{2} \\ {x}^{2} = 4 {x}^{2} - 4x + 1 \\ 3 {x}^{2} - 4x + 1 = 0 \\ (x - 1)(x - \frac{1}{3} ) = 0 \\ \therefore \: x = 1 \: or \: x = \frac{1}{3} [/tex]

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