Respuesta :

ghaithgh

The choose a. 3x+12

[tex]( \frac{f}{g} )(x) = \frac{3 {x}^{2} - 48 }{x - 4} = \frac{3( {x}^{2} - 16) }{x - 4} \\ \\ = \frac{3(x - 4)(x + 4)}{x -4} \\ \\ = 3(x + 4) \\ = 3x + 12[/tex]

I hope I helped you^_^