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  • 22-08-2021
  • Mathematics
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The gradient of the curve
[tex] y = {3x}^{x2} + 11x + 7 [/tex]
at point p(x,y) is -1. Find the coirdinate of P.​

Respuesta :

Аноним Аноним
  • 22-08-2021

Answer:

Coordinate of P is (-2, -3)

Step-by-step explanation:

Gradient is the derivative of the curve:

[tex]y = {3x}^{2} + 11x + 7 \\ \\ \frac{dy}{dx} = 6x + 11[/tex]

but dy/dx is -1 :

[tex]6x + 11 = - 1 \\ 6x = - 12 \\ x = - 2[/tex]

substitute for x :

[tex]y = 3( - 2) {}^{2} + 11( - 2) + 7 \\ y = - 3[/tex]

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