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  • 25-07-2021
  • Mathematics
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Find the missing side lengths

Find the missing side lengths class=

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Аноним Аноним
  • 27-07-2021

Answer:

[tex]Sin \: 60=\frac{\sqrt{3} }{u}[/tex]

[tex]u=\sqrt{3} /sin\:60[/tex]

[tex]u=\sqrt{3} /\sqrt{3} /2[/tex]

[tex]u=2[/tex]

..........................

[tex]Cos\: 60=\frac{v}{2}[/tex]

[tex]v=2\: cos\:60[/tex]

[tex]v=2(\frac{1}{2})[/tex]

[tex]v=1[/tex]

OAmalOHopeO

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