Answer:
Step-by-step explanation:
As per the question we are looking for a number which is a multiple of the greatest possible exponent of 3.
Let's see the exponents of 3 within 1-2017 interval:
- 3¹ = 3, 3²= 9, 3³ = 27, 3⁴ = 81, 3⁵ = 243, 3⁶ = 729, 3⁷ = 2187 > 2017
As we see the greatest exponent of 3 is 729.
There are two multiples of 729 in the given interval:
- 729*1 = 729 and 729*2 = 1458
So the last number is 1458
