ericzeferino42
ericzeferino42 ericzeferino42
  • 25-06-2021
  • Mathematics
contestada

Find all solutions to the equation in the interval [0, 2pi). COS X = sin 2x​

Respuesta :

surjithayer10otahza surjithayer10otahza
  • 06-07-2021

Answer:

Step-by-step explanation:

cos x=sin 2x

sin 2x-cos x=0

2 sin x cos x-cos x=0

cos x(2 sin x-1)=0

either cos x=0

[tex]x=\frac{\pi }{2},\frac{3\pi }{2}[/tex]

or

2 sin x-1=0

[tex]sin x=\frac{1}{2} =sin (\frac{\pi }{6}),sin(\pi -\frac{\pi }{6} )\\x=\frac{\pi }{6} ,\frac{5 \pi }{6}[/tex]

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