tsyordi33 tsyordi33

25-06-2021
Physics

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A 2kg ball is attached to a 0.80m string and whirled in a horizontal circle at a constant speed of 6m/s .the work done on the ball during each revolution is.

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pphtins pphtins

25-06-2021

Answer:

work done = kinetic energy in a SHM

= 1/2mW²r²

but ; w = v/r

therefore ; w:d = 1/2mv²/r² × r²

= 1/2 mv²

= 1/2 × 2×6²

= 36J

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