Answer:
-6 and -1
Step-by-step explanation:
The excluded values are the values of x that satisfy [tex]2x^{2} + 14x + 12 = 0[/tex]
Let us solve the equation [tex]2x^{2} + 14x + 12 = 0[/tex]
It's a quadratic equation
Thus, let us calculate the discriminant Δ
Δ [tex]= 14^{2} - 4 .2.12 = 100[/tex]
the discriminant is greater than 0, so the equation has two solutions
[tex]x = \frac{-14 - 10}{4} = \frac{-24}{4} = -6[/tex] or [tex]x = \frac{-14+10}{4} = \frac{-4}{4} = -1[/tex]
the excluded values are -6 and -1
