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A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the horizontal. If air resistance is negligible, what is the value of the kinetic energy of the ball as it hits the ground?

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okpalawalter8

Answer:

[tex]K.E = 163 J[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=4.1kg[/tex]

Height [tex]h=4m[/tex]

Speed [tex]V=1m/s[/tex]

Angle [tex]\theta= 2 \textdegree[/tex]

Generally the equation for K.E is mathematically given by

Since

The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

Therefore

 [tex]K.E=mgH + 0.5mV^2[/tex]

 [tex]K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5[/tex]

 [tex]K.E = 163 J[/tex]

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