dancezepeto31
dancezepeto31 dancezepeto31
  • 24-06-2021
  • Mathematics
contestada


cosa \div tana = 1 - sin ^{2} a \div \sqrt{1 - cos ^{2} } acosa÷tana=1−sin
2
a÷
1−cos
2

​
a
​

Respuesta :

Sueraiuka
Sueraiuka Sueraiuka
  • 24-06-2021

Step-by-step explanation:

Hey there!

LHS

[tex] = \frac{ \cos(a) }{ \tan(a) } [/tex]

Use tan A = sin A/cosA

[tex] = \cos(a) \times \frac{ \cos(a) }{ \sin(a) } [/tex]

[tex] = \frac{ { \cos(a) }^{2} }{ \sin(a) } [/tex]

Then, Use formula cos²A = 1-sin²A and sinA = √(1-cos²A)

[tex] = \frac{1 - { \sin(a) }^{2} }{ \sqrt{ - { \cos(a) }^{2} } } [/tex]

Proved!

Hope it helps!

Answer Link

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