leyenphuongehe leyenphuongehe
  • 22-06-2021
  • Mathematics
contestada

cho số phức z thỏa mãn 2iz-5+i=i-(z-2i) tính modun của số phức w=z-1+i

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LammettHash
LammettHash LammettHash
  • 22-06-2021

Solve the given equation for z :

2iz - 5 + i = i - (z - 2i )

2iz - 5 = 2i - z

(2i + 1) z = 2i + 5

z = (2i + 5)/(2i + 1)

z = (2i + 5)/(2i + 1) × (2i - 1)/(2i - 1)

z = (4i ² + 10i - 2i - 5) / (4i ² - 1)

z = (8i - 9)/(-5)

z = 9/5 - 8/5 i

Then

w = z - 1 + i = 4/5 - 3/5 i

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