Answer:
The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.
A Let tower be AB
Let point be C
Distance of point C from foot of tower = 30m Hence,
BC = 30m
Angle of elevation = 30°
So < ACB = 30°
Since tower is vertical,
< ABC = 90°
