pjessie32171 pjessie32171
  • 24-04-2021
  • Mathematics
contestada

write an equation of a line passing thru the point (-4,-11) and perpendicular to the line 4x+5y= -45​

Respuesta :

rococo908
rococo908 rococo908
  • 24-04-2021

Answer:

y = 5/4x - 6

Step-by-step explanation:

First, put 4x + 5y= -45​ in y = mx + b form

4x + 5y= -45​

5y = -4x - 45

y = -4/5x - 9

So, the slope is -4/5. Perpendicular lines have a opposite reciprocal slope, so the line's slope will be 5/4

To find the equation of the perpendicular line, plug in the slope and given point into y = mx + b, and solve for b

y = mx + b

-11 = 5/4(-4) + b

-11 = -5 + b

-6 = b

Plug in b and the slope into y = mx + b

y = 5/4x - 6

So, the equation is y = 5/4x - 6

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