Answer:
Point B
Step-by-step explanation:
Ok let's see how we should solve it.
If [tex]x = \sqrt{11}[/tex] then [tex]x^2 = 11[/tex]
So we need to find the point that, when squared, seems to give us 11.
Because [tex]3^2 = 9 < 11[/tex] and [tex]4^2 = 16 > 11[/tex], we know that the point we're looking for lies between 3 and 4 - only Point B fits.
