Answer:
4.22in
Step-by-step explanation:
Given data
Volume= 601in^3
Height= 10.7in
Radius= ??
The expression for the volume of a cylindrical bucket is
V=πr^2h
substitute
601= 3.14*r^2*10.7
601= 33.598r^2
601/33.598= r^2
17.88=r^2
square both sides
r= √17.88
r= 4.22 in
Hence the radius of the bucket is 4.22in
