Mariel0521 Mariel0521
  • 23-04-2021
  • Mathematics
contestada

Please help .. would be appreciated

Please help would be appreciated class=

Respuesta :

Hrishii
Hrishii Hrishii
  • 23-04-2021

Answer:

x = 30

Step-by-step explanation:

[tex] \triangle JLK\sim\triangle PQR[/tex] (given)

[tex] \therefore \frac{JL}{PQ}=\frac{LK}{QR} [/tex]

(corresponding sides of similar triangles)

[tex] \therefore \frac{20}{x}=\frac{22}{33} [/tex]

[tex] \therefore \frac{20}{x}=\frac{2}{3} [/tex]

[tex] \therefore x=\frac{20\times 3}{2} [/tex]

[tex] \therefore x=\frac{60}{2} [/tex]

[tex] \therefore x=30 [/tex]

Or using scale factor:

Scale factor = 33/22 = 3/2

x = 20*3/2

x = 10*3

x = 30

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