angelamarie198307 angelamarie198307
  • 23-04-2021
  • Mathematics
contestada

Special right triangles. find the value of x?
hypotenuse = leg ×
[tex] \sqrt{2} [/tex]
​

Special right triangles find the value of x hypotenuse leg tex sqrt2 tex class=

Respuesta :

akposevictor
akposevictor akposevictor
  • 28-04-2021

Answer:

x = (9√2)/2

Step-by-step explanation:

Reference angle = 45°

Hypotenuse length = 9

Adjacent length = x

Apply the trigonometric ratio CAH:

Cos 45° = Adj/Hyp

Cos 45° = x/9

Multiply both sides by 9

9*Cos 45 = x

9*1/√2 = x (cos 45 = 1/√2)

9/√2 = x

Rationalize

(9*√2)/2 = x

x = (9√2)/2

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