Respuesta :

gayanepoghosyan

Answer:

B

Step-by-step explanation:

in complex numbers i²=-1

[tex]\frac{7-i}{3-i}= \frac{(7-i)(3+i)}{(3-i)(3+i)}= \frac{21+3i+7i+i^{2} }{3^{2} -i^{2} }= \frac{21+10i-1}{9+1}== \frac{20+10i}{10}=2+i[/tex]