An airplane travels about 1500 km in a straight line between Toronto and
Winnipeg. However, the plane must climb
to 10 000 m during the first 200 km. Then
it must descend 10 000 m during the final
300 km.
question:
The airplane averages a speed of
600 km/h. Do climbing and descending
10 000 m add hours, minutes, or
seconds to the flight?
Please explain :)

Based on the given problem above, it requires a trigonometric solution. So here it goes: The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km So add the given results above with 500 km and this will be the additional distance that plane moves through the air. The answer would be in the unit meters. ((10√401 +10√901−500)∗1000)=416 meters Hope this is the answer that you are looking for.